Description
Given a non-negative integer
c
, your task is to decide whether there’re two integers
a
and
b
such that a2+b2=c .
Example 1:
Input: 5
Output: True
Explanation:1 * 1 + 2 * 2 = 5
Example 2:
Input: 3
Output: False
Analysis
這道題不需要很複雜的數論知識,純暴力也可以過,但兩層循環周遊可能的數字會TLE,要利用
a
,
b
兩數之間的關系,一層循環即可,直接利用sqrt()函數和強制類型轉換即可AC。
Code
class Solution {
public:
bool judgeSquareSum(int c) {
for (long a = ; a * a <= c; a++){
double b = sqrt(c - a * a);
if ((int)b == b)
return true;
}
return false;
}
};
Appendix
- Link: https://leetcode.com/problems/sum-of-square-numbers/
- Run Time: 13ms