Max Factor
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 3644 Accepted Submission(s): 1167
Problem Description To improve the organization of his farm, Farmer John labels each of his N (1 <= N <= 5,000) cows with a distinct serial number in the range 1..20,000. Unfortunately, he is unaware that the cows interpret some serial numbers as better than others. In particular, a cow whose serial number has the highest prime factor enjoys the highest social standing among all the other cows.
(Recall that a prime number is just a number that has no divisors except for 1 and itself. The number 7 is prime while the number 6, being divisible by 2 and 3, is not).
Given a set of N (1 <= N <= 5,000) serial numbers in the range 1..20,000, determine the one that has the largest prime factor.
Input * Line 1: A single integer, N
* Lines 2..N+1: The serial numbers to be tested, one per line
Output * Line 1: The integer with the largest prime factor. If there are more than one, output the one that appears earliest in the input file.
Sample Input
4
36
38
40
42
Sample Output
38
求几个数的最大质因子最大的那个数
#include <iostream>
#include<algorithm>
#include<stdio.h>
#include<string.h>
#include<math.h>
using namespace std;
int main()
{
int i,j,a[20001]={0,1};
for(i=2;i<20001;i++) //a[t]保存t的最大素因数
{
if(a[i]==0)
{
for(j=i;j<20001;j+=i)
{
a[j]=i;
}
}
}
int n;
int Max=0;
int x;
int ans=0;
while(scanf("%d",&n)!=EOF)
{
ans=0;
Max=0;
while(n--)
{
scanf("%d",&x);
if(a[x]>Max)
{
Max=a[x];
ans=x;
}
}
printf("%d\n",ans);
}
return 0;
}