Although quarterback Aaron Rodgers made it clear when he got into a conflict with the Green Bay Packers last season, he didn't care if he became the highest-paid player in history. But if he does stay at the Packers this season, I don't think he'll mind that. According to Ian Rappoport, a well-known reporter on the NFL's official website, because the packers really can't provide him with a long-term contract, the two sides are working hard to reach a short-term agreement that makes Rogers the highest-paid player in the league.
Of course, whether Rogers can get the money will depend on whether he stays in the Packers in 2022, and so far there is still no indication whether the regular season MVP winner of the past two years stays in Green Bay or is far away. But if Rogers decides to continue his career in a new city, it will require the packer's consent, as he is still under contract with the packer after all.
If Rodgers becomes the league's highest-paid player, that means he'll have to make at least $45 million a year to match Chiefs quarterback Patrick Mahomes. While this will further compress the packer's future salary cap, for a player of Rogers' level, such a high salary is not excessive.
Packers General Manager Brian Gutconst recently spoke about Rogers' future with his successor Devante Adams. He said that despite the salary cap problem, if Rogers can stay, the team will do its best to keep Adams, and the Packers will still be a very competitive team, which he is "very confident".
However, the reality facing the team is still quite grim, although the contract of defensive interceptor Kenny Clark and running back Aaron Jones has been restructured continuously, but the team's current salary cap is still more than $40 million. Rogers himself said in a guest appearance last week that while he had not identified a clear attribution, he hoped to be able to complete negotiations with the packers soon. Presumably, the deadline for this negotiation is March 17, Beijing time, the official opening hours of the free market.
(Aibao)