Given a set of distinct integers, nums, return all possible subsets.
Note: The solution set must not contain duplicate subsets.
For example,
If nums =
[1,2,3]
, a solution is:
[
[3],
[1],
[2],
[1,2,3],
[1,3],
[2,3],
[1,2],
[]
]
===================================================================
題目連結:https://leetcode.com/problems/subsets/
題目大意:求出給定集合的所有子集。
思路:深搜(dfs)或寬搜(bfs)。
參考代碼:
class Solution {
public:
vector<vector<int>> subsets(vector<int>& nums) {
int n = nums.size() ;
sort ( nums.begin() , nums.end() ) ;
vector <int> temp ;
vector < vector <int> > ans ( 1 , temp ) ;
queue < vector <int> > q ;
q.push ( temp ) ;
while ( ! q.empty() )
{
temp = q.front() ;
q.pop() ;
for ( int i = 0 ; i < n ; i ++ )
{
if ( temp.empty() || nums[i] > temp.back() )
{
vector <int> tt = temp ;
tt.push_back ( nums[i] ) ;
ans.push_back ( tt ) ;
q.push ( tt ) ;
}
}
}
return ans ;
}
};