螺旋矩阵II
- 做题博客链接
- 题目链接
- 描述
- 示例
- 初始代码模板
- 代码
做题博客链接
https://blog.csdn.net/qq_43349112/article/details/108542248
题目链接
https://leetcode-cn.com/problems/spiral-matrix-ii/
描述
给你一个正整数 n ,生成一个包含 1 到 n2 所有元素,且元素按顺时针顺序螺旋排列的 n x n 正方形矩阵 matrix 。
提示:
1 <= n <= 20
示例
示例 1:

输入:n = 3
输出:[[1,2,3],[8,9,4],[7,6,5]]
示例 2:
输入:n = 1
输出:[[1]]
初始代码模板
class Solution {
public int[][] generateMatrix(int n) {
}
}
代码
class Solution {
public int[][] generateMatrix(int n) {
int[][] arr = new int[n][n];
int count = 1;
int left = 0;
int right = n - 1;
int top = 0;
int down = n - 1;
int finalVal = n * n;
while (count <= finalVal) {
for (int i = left; i <= right && count <= finalVal; i++) {
arr[top][i] = count++;
}
top++;
for (int i = top; i <= down && count <= finalVal; i++) {
arr[i][right] = count++;
}
right--;
for (int i = right; i >= left && count <= finalVal; i--) {
arr[down][i] = count++;
}
down--;
for (int i = down; i >= top && count <= finalVal; i--) {
arr[i][left] = count++;
}
left++;
}
return arr;
}
}