Problem Description
Given a positive integer N, you should output the most right digit of N^N.
Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single positive integer N(1<=N<=1,000,000,000).
Output
For each test case, you should output the rightmost digit of N^N.
Sample Input
2
3
4
Sample Output
7
6
package hlh;
import java.util.Scanner;
public class p1061 {
// 用来找规律: 1~10:1 4 7 6 5 6 3 6 9 0
// 用来找规律: 11~20:1 6 3 6 5 6 7 4 9 0
// 用来找规律: 21~30:1 4 7 6 5 6 3 6 9 0
// 用来找规律: 31~40:1 6 3 6 5 6 7 4 9 0
public static void main(String[] args) {
/* for(int x=111;x<=120;x++){
int temp = x%10;
for(int i=1;i<x;i++){
temp = (temp*x%10)%10;
}
System.out.print(temp+" ");
}*/
Scanner sc = new Scanner(System.in);
int t=sc.nextInt();
while(t-->){
int a [] = {,,,,,,,,,,,,,,,,,,,};
int x =sc.nextInt();
x = x%;
if(x%==){
System.out.println();
continue;
}
System.out.println(a[x-]);
}
}
}