题意:
一只吸血鬼,有n条路给他走,每次他随机走一条路,每条路有个限制,如果当时这个吸血鬼的攻击力大于等于某个值,那么就会花费t天逃出去
否则花费1天的时间,并且攻击力增加,问他逃出去的期望
分析:
dp[i]:=攻击力为i逃出去的期望,逆序递推或者记忆化搜索都行
代码:
//
// Created by TaoSama on 2015-10-09
// Copyright (c) 2015 TaoSama. All rights reserved.
//
//#pragma comment(linker, "/STACK:1024000000,1024000000")
#include <algorithm>
#include <cctype>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <string>
#include <set>
#include <vector>
using namespace std;
#define pr(x) cout << #x << " = " << x << " "
#define prln(x) cout << #x << " = " << x << endl
const int N = + , INF = , MOD = + ;
int n, f, c[];
double dp[N];
bool vis[N];
double get(int x) {
return floor(( + sqrt()) / * x * x);
}
double dfs(int f) {
if(vis[f]) return dp[f];
vis[f] = true;
dp[f] = ;
for(int i = ; i <= n; ++i) {
if(f > c[i]) dp[f] += get(c[i]);
else dp[f] += + dfs(f + c[i]);
}
dp[f] /= n;
return dp[f];
}
int main() {
#ifdef LOCAL
freopen("C:\\Users\\TaoSama\\Desktop\\in.txt", "r", stdin);
// freopen("C:\\Users\\TaoSama\\Desktop\\out.txt","w",stdout);
#endif
ios_base::sync_with_stdio();
while(scanf("%d%d", &n, &f) == ) {
for(int i = ; i <= n; ++i) scanf("%d", c + i);
memset(vis, false, sizeof vis);
printf("%.3f\n", dfs(f));
}
return ;
}