HDU2051 Bitset

Bitset

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 21100    Accepted Submission(s): 15644

Problem Description Give you a number on base ten,you should output it on base two.(0 < n < 1000)  

Input For each case there is a postive number n on base ten, end of file.  

Output For each case output a number on base two.  

Sample Input

1
2
3
        

Sample Output

1
10
11
        

#include <stdio.h>

int a[1005][10];

int main(){

	int i,j,n;
	
	for(i = 1; i <= 1000; i ++)
	{
		j = 10;
		int temp = i;
		
		while(temp){
			a[i][j --] = temp % 2;
			temp /= 2;
		}
	}
	
	while(scanf("%d",&n) != EOF){
		int flag = 0;
		for(j = 1; j <= 10; j ++){
			if(a[n][j])
				flag = 1;
			
			if(flag)
				printf("%d",a[n][j]);
		}
		putchar('\n');
	}
	return 0;
}