根據字典的值大小對字典進行排序

一：

In [76]: d = {x:random.randint(60,100) for x in 'abcdefg'}

In [86]: l=list(zip(d.values(),d.keys()))

In [87]: l=sorted(l)#從小到大排列

二：

In [97]: d.items()

Out[97]: dict_items([('a', 80), ('b', 90), ('c', 87), ('d', 70), ('e', 79), ('f', 97), ('g', 92)])

In [98]: sorted(d.items(),key=lambda x:x[1])

Out[98]: [('d', 70), ('e', 79), ('a', 80), ('c', 87), ('b', 90), ('g', 92), ('f', 97)]