LeetCode Array Easy 167. Two Sum II - Input array is sorted

 Description

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.

The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2.

Note:

• Your returned answers (both index1 and index2) are not zero-based.
• You may assume that each input would have exactly one solution and you may not use the same element twice.

Example:

Input: numbers = [2,7,11,15], target = 9
Output: [1,2]
Explanation: The sum of 2 and 7 is 9. Therefore index1 = 1, index2 = 2.      

題目描述，給定一個已排序的數組，和一個目标值，計算數組中的兩個值的和等于目标值時的位置，這裡位置不從0開始。

思路： 數組是以排序的，則使用兩個指針，分别指向數組的頭尾，當兩數相加小于目标值是則頭指針遞增一位，當相加大于目标值值，尾指針遞減。

下面是代碼，感覺還有優化的地方。先貼出來。

public int[] TwoSum(int[] numbers, int target)
        {
            int[] result = new int[2];
            int lo=0, hi=numbers.Length-1;
            while(lo < hi)
            {
                if (numbers[lo] + numbers[hi] < target) lo++;
                else if (numbers[lo] + numbers[hi] > target) hi--;
                else
                    break;
            }
            result[0] = lo + 1;
            result[1] = hi + 1;
            return result;
        }      

轉載于:https://www.cnblogs.com/c-supreme/p/9559971.html