Description:
International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: “a” maps to “.-“, “b” maps to “-…”, “c” maps to “-.-.”, and so on.
For convenience, the full table for the 26 letters of the English alphabet is given below:
[".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
Now, given a list of words, each word can be written as a concatenation of the Morse code of each letter. For example, “cab” can be written as “-.-.-….-“, (which is the concatenation “-.-.” + “-…” + “.-“). We’ll call such a concatenation, the transformation of a word.
Return the number of different transformations among all words we have.
Example:
Input: words = ["gin", "zen", "gig", "msg"]
Output: 2
Explanation:
The transformation of each word is:
“gin” -> “–…-.”
“zen” -> “–…-.”
“gig” -> “–…–.”
“msg” -> “–…–.”
There are 2 different transformations, “–…-.” and “–…–.”.
Note:
The length of words will be at most 100.
Each words[i] will have length in range [1, 12].
words[i] will only consist of lowercase letters.
Java
class Solution {
public int uniqueMorseRepresentations(String[] words) {
String[] table = new String[] {".-","-...","-.-.","-..",".","..-.","--.","....","..",
".---","-.-",".-..","--","-.","---",".--.","--.-",".-.",
"...","-","..-","...-",".--","-..-","-.--","--.."};
Set<String> transformation = new HashSet<>();
for (String word : words) {
StringBuilder sb = new StringBuilder();
for (int i = 0; i < word.length(); i++) {
sb.append(table[word.charAt(i) - 'a']);
}
if