shell例題2

1.s="abc:    def"

  echo $s

  abc: def

  利用s變量輸出orgdef?

  #   echo org${s##* }

  orgdef

  #

2.strs='61.174.144.22107;35' 去掉後5位字元?

  1)echo ${strs%?????}

  2)echo ${strs:0:${#strs}-5}

  3)echo $strs|sed 's/.....$//'

  4)echo $strs|sed -r 's/[;0-9]{5}$//'

  5)echo $strs|cut -b 1-$((${#strs}-5))

  6)echo $strs|awk '{print substr($0,1,length($0)-5)}'

 sed,cut,awk......很全哦

3.aaa="[2011-07-07 14:14:15:747]RUN AB81449/AB81449_NTC023:CF FAILURE"

  提取RUN?

  echo $aaa|tr ']' ' '|cut -d ' ' -f3

  echo ${aaa#*]}|cut -d ' ' -f1

4.注意每一行前都有若幹空格

        qc-android/device/common

           qc-android/device/htc/common

           qc-android/device/htc/passion

  變成如下效果

  writable = qc-android/platform/manifest

  cat $file|sed 's/^ *//;s/^/writable = /'

5.ksysguardd-4.5.5-1.fc13.x86_64

  gd-devel-2.0.35-11.fc13.x86_64

  gwave-2-18.20090213snap.fc13.x86_64

  fontconfig-2.8.0-1.fc13.i686

  libbeagle-0.3.9-5.fc12.x86_64

  pstoedit-3.45-9.fc12.x86_64

  要求輸出類似ksysguardd-*

  cat $file|awk -F '[0-9]' '{print $1"*"}'

  cat $file|sed 's/[0-9].*$/\*/'

  cat $file|awk '{sub(/[0-9].*/,"*")}1'

  ## 估計1代替的print $0,awk可惜隻學了點基礎的