POJ2406Power Strings

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power strings

time limit: 3000ms

memory limit: 65536k

total submissions: 30293

accepted: 12631

description

given two strings a and b we define a*b to be their concatenation. for example, if a = "abc" and b = "def" then a*b = "abcdef". if we think of concatenation as multiplication, exponentiation by a non-negative integer is defined in the normal way: a^0 = "" (the

empty string) and a^(n+1) = a*(a^n).

input

each test case is a line of input representing s, a string of printable characters. the length of s will be at least 1 and will not exceed 1 million characters. a line containing a period follows the last test case.

output

for each s you should print the largest n such that s = a^n for some string a.

sample input

sample output

hint

this problem has huge input, use scanf instead of cin to avoid time limit exceed.

source

题意:不多解释

这题书上说是用kmp来做，自己开始也尝试这样做，但后来发现根本就没有这个必要~~~几个简单的字符串处理函数就可以a掉了

代码: