HDU 5853 Jong Hyok and String

Problem Description

Jong Hyok loves strings. One day he gives a problem to his friend you. He writes down n strings Pi in front of you, and asks m questions. For i-th question, there is a string Qi. We called strange set(s) = {(i, j) | s occurs in Pi and j is the position of its last character in the current occurence}. And for ith question, you must answer the number of different strings t which satisfies strange set(Qi) = strange set(t) and t is a substring of at least one of the given n strings.

Input

First line contains T, a number of test cases.

For each test cases, there two numbers n, m and then there are n strings Pi and m strings Qj.(i = 1…n, j = 1…m)

1 <= T <= 10

1 <= n <= 100000

1 <= m<= 500000

1 <=|Pi|<=100000

1 <=|Qi|<=100000

∑ni=1|Pi|≤100000

File size is less than 3.5 megabytes.

Output

For each test case, first line contains a line “Case #x:”, x is the number of the case.

For each question, you should print one integer in one line.

Sample Input

1

2 2

aba

ab

a

ab

Sample Output

Case #1:

1

2

Hint

#include<set>
#include<map>
#include<ctime>
#include<cmath>
#include<stack>
#include<queue>
#include<bitset>
#include<cstdio>
#include<string>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<functional>
#define rep(i,j,k) for (int i = j; i <= k; i++)
#define per(i,j,k) for (int i = j; i >= k; i--)
#define lson x << 1, l, mid
#define rson x << 1 | 1, mid + 1, r
#define fi first
#define se second
#define mp(i,j) make_pair(i,j)
#define pii pair<int,int>
using namespace std;
typedef long long LL;
const int low(int x) { return x&-x; }
const double eps = 1e-8;
const int INF = 0x7FFFFFFF;
const int mod = 1e9 + 7;
const int N = 1e5 + 10;
const int read()
{
    char ch = getchar();
    while (ch<'0' || ch>'9') ch = getchar();
    int x = ch - '0';
    while ((ch = getchar()) >= '0'&&ch <= '9') x = x * 10 + ch - '0';
    return x;
}
int T, n, m, cas = 0;
char s[N];

class SAM
{
    const static int maxn = 500005;   //节点个数    
    const static int size = 27;     //字符的范围    
    const static char base = 'a';     //字符的基准    

    class node
    {
    public:
        node *fa, *next[size];
        int len, cnt;
        node* clear(int x, int y)
        {
            fa = 0; len = x; cnt = y;
            memset(next, 0, sizeof(next));
            return this;
        }
    }nd[maxn];                      //节点的设置    

    int tot;                        //总节点数    
public:
    node *root, *last; //根节点,上一个节点  

    void clear()
    {
        last = root = &nd[tot = 0];
        nd[0].clear(0, 0);
    }                               //初始化    
    void insert(char ch, int maxlen)
    {
        node *p = last, *np = nd[++tot].clear(p->len + 1, maxlen);
        last = np;
        int x = ch - base;
        while (p&&p->next[x] == 0) p->next[x] = np, p = p->fa;
        if (p == 0) { np->fa = root; return; }

        node* q = p->next[x];
        if (p->len + 1 == q->len) { np->fa = q; return; }

        node *nq = nd[++tot].clear(p->len + 1, q->cnt);
        memcpy(nq->next, q->next, sizeof q->next);
        nq->fa = q->fa;
        q->fa = np->fa = nq;
        while (p &&p->next[x] == q) p->next[x] = nq, p = p->fa;
        return;
    }
    void work()
    {
        scanf("%s", s);
        node * q = root;
        for (int i = 0; s[i]; i++)
        {
            int x = s[i] - base;
            if (!q->next[x]) { printf("0\n"); return; }
            q = q->next[x];
        }
        printf("%d\n", min(q->len, q->cnt) - q->fa->len);
    }
}sam;

int main()
{
    scanf("%d", &T);
    while (T--)
    {
        scanf("%d%d", &n, &m);
        sam.clear();
        rep(i, 1, n)
        {
            scanf("%s", s);
            for (int j = 0; s[j]; j++) sam.insert(s[j], j + 1);
            sam.insert('z' + 1, 0);
        }
        printf("Case #%d:\n", ++cas);
        rep(j, 1, m) sam.work();
    }
    return 0;
}