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php 数组 where,PHP将数组解析并传递给where子句作为查询条件

给定一数组 $galleries = array(1,2,5),我想要一个SQL查询,它在WHERE子句中使用数组的值,如:

SELECT *

FROM galleries

WHERE id =

如何生成此查询字符串以用于MySQL?

最简单的方法:implode

数组元素的值是整型:

$query = "SELECT * FROM `$table` WHERE `$column` IN(".implode(',',$array).")";

数组元素的值是字符串:

$query = "SELECT * FROM `$table` WHERE `$column` IN('".implode("','",$array)."')";

对于具有转义功能的MySQLi:

$ids = array_map(function($a) use($mysqli) {

return is_string($a) ? "'".$mysqli->real_escape_string($a)."'" : $a;

}, $ids);

$ids = join(',', $ids);

$result = $mysqli->query("SELECT * FROM galleries WHERE id IN ($ids)");

对于准备好声明的PDO:

$qmarks = implode(',', array_fill(0, count($ids), '?'));

$sth = $dbh->prepare("SELECT * FROM galleries WHERE id IN ($qmarks)");

$sth->execute($ids);