回溯
给h和k的意思是在k种邮票中选h个邮票
基本的连续邮资问题
15226160 | 165 | Stamps | Accepted | C++ | 0.062 | 2015-03-27 07:21:37 |
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
const int maxn = 222;
const int maxd = 15;
int h,k;
int vis[maxn];
int array[maxd];
int ans_value;
int ans_array[maxd];
void dfs(int step,int arr[],int size,int sum){
vis[sum] = 1;
if(step == h){
return;
}
for(int i = 0; i < size; i++)
dfs(step + 1,arr,size,sum + arr[i]);
}
void dfs2(int step,int pos,int arr[]){
dfs(0,arr,step,0);
int next;
for(int i = 1; ; i++)
if(!vis[i]){
next = i;
break;
}
if(step == k){
if(next - 1 > ans_value){
for(int i = 0; i < step; i++)
ans_array[i] = arr[i];
ans_value = next - 1;
}
return;
}
int vis_temp[maxn];
memcpy(vis_temp,vis,sizeof(vis));
for(int i = pos; i <= next; i++){
arr[step] = i;
dfs2(step + 1,i + 1,arr);
memcpy(vis,vis_temp,sizeof(vis_temp));
}
}
int main(){
while(scanf("%d%d",&h,&k) && h){
memset(vis,0,sizeof(vis));
array[0] = 1;
ans_value = 0;
dfs2(1,2,array);
for(int i = 0; i < k; i++)
printf("%3d",ans_array[i]);
printf(" ->%3d\n",ans_value);
}
return 0;
}