在官方文档中,推荐当我们使用
QStackedWidget
元件时,使用
QComboBox
或者
QListWidget
元件与它相关联起来进行不同页的切换,那么有没有可能我们将按键元件和它关联起来进行不同页的操作呢?答案是可以的,这里记录一下,请看如下代码:
# -*- coding:utf-8 -*-
import sys
from PyQt5.QtWidgets import QApplication, QListWidget, QWidget, QStackedWidget, QHBoxLayout, QGridLayout, \
QPushButton
class App(QWidget):
def __init__(self, parent=None):
super(App, self).__init__(parent)
# 创建左侧按键元件
self.btn1 = QPushButton("按钮1")
self.btn2 = QPushButton("按钮2")
self.btn3 = QPushButton("按钮3")
# 设置按键点击属性
self.btn1.clicked.connect(self.display)
self.btn2.clicked.connect(self.display)
self.btn3.clicked.connect(self.display)
# 创建左侧布局
self.left_layout = QGridLayout()
self.left_layout.addWidget(self.btn1)
self.left_layout.addWidget(self.btn2)
self.left_layout.addWidget(self.btn3)
# 创建左侧组件
self.left_widget = QWidget()
self.left_widget.setLayout(self.left_layout)
# 创建右侧分页
self.stack1 = QWidget()
self.stack2 = QWidget()
self.stack3 = QWidget()
# 创建右侧分页各个组件
self.initStack1()
self.initStack2()
self.initStack3()
# 创建整体页组件,并将三个分页添加到主页上
self.Stack = QStackedWidget()
self.Stack.addWidget(self.stack1)
self.Stack.addWidget(self.stack2)
self.Stack.addWidget(self.stack3)
# 创建主组件布局
self.main_layout = QHBoxLayout()
# 向主组件布局中添加左右两个整体组件
self.main_layout.addWidget(self.left_widget)
self.main_layout.addWidget(self.Stack)
# 设置主组件的布局为创建的主布局
self.setLayout(self.main_layout)
def initStack1(self):
layout = QHBoxLayout()
list1 = QListWidget()
list1.insertItem(0, "第一页")
layout.addWidget(list1)
self.stack1.setLayout(layout)
def initStack2(self):
layout = QHBoxLayout()
list1 = QListWidget()
list1.insertItem(0, "第二页")
layout.addWidget(list1)
self.stack2.setLayout(layout)
def initStack3(self):
layout = QHBoxLayout()
list1 = QListWidget()
list1.insertItem(0, "第三页")
layout.addWidget(list1)
self.stack3.setLayout(layout)
def display(self):
sender = self.sender()
if sender.text() == "按钮1":
self.Stack.setCurrentIndex(0)
elif sender.text() == "按钮2":
self.Stack.setCurrentIndex(1)
elif sender.text() == "按钮3":
self.Stack.setCurrentIndex(2)
def main():
app = QApplication(sys.argv)
window = App()
window.show()
sys.exit(app.exec())
if __name__ == '__main__':
main()
至此,使用按钮来实现
QStackedWidget
切换被完成。效果图如下:
