【单片机】LED16*16点阵显示实验

• ​​一、操作目的​​
• ​​二、操作内容​​
• ​​三、接线图​​
• ​​四、程序清单​​
• ​​五、代码详解​​

一、操作目的

• 利用单片机并行控制LED点阵显示。
• 掌握单片机与LED点阵块之间接口电路设计及编程。
• 利用取模软件建立标准字库，编制程序实现点阵循环左移显示汉字。

二、操作内容

三、接线图

四、程序清单

;L-SAO-1,CTL-MODE:BING XIN KO
  XPB  EQU  0FF29H      ;L-SAO-2
;---------------------------------------------------------------
  XPC  EQU  0FF2AH      ;H-CODE-2
  XPCTL  EQU  0FF2BH
START:    MOV DPTR,#XPCTL    ;THIS IS A PROGRAM OF L-MOVE-WORD
  MOV A,#80H
  MOVX @DPTR,A      ;WR-CTL
  CALL OFFLED      ;OFFLED
  CLR 00H
  MOV R6,#28H
  MOV R7,#0FFH
;----------------------------------------
X0:        MOV R0,#00H      ;ONE-WORD-FIRST-NUM
X1:      CALL DEL1        ;QI
  INC R0          ;RL-1-BIT
  mov a,r0
  anl a,#0fh
  cjne a,#00h,l2
  mov a,#10h
  add a,r0
  mov r0,a
l2:      CJNE R0,#00H,X1
    SJMP X0
;---------------------------------------------------------------
DISPW:      PUSH 00H        ;DISP-ONE-WORD
    MOV R1,#01H      ;L-NUM
    CLR C
DISP1:    MOV A,R0        ;BH1
  MOV DPTR,#TAB
  MOVC A,@A+DPTR
  MOV DPTR,#XPC
  MOVX @DPTR,A
;-------------------------------------------
  mov a,#10h
  add a,r0
  MOV DPTR,#TAB
  MOVC A,@A+DPTR
  MOV P1,A
  INC R0            ;BH2
;-------------------------------------------
  mov a,r0
  anl a,#0fh
  cjne a,#00h,l1
  mov a,#10h
  add a,r0
  mov r0,a
  clr c            ;!!!!!
l1:      MOV DPL,R6          ;XPA/XPB
  MOV DPH,R7
  MOV A,R1          ;L0----L7
  CPL A
  MOVX @DPTR,A
  mov r3,#80h
  djnz r3,$
  CALL OFFLED
  MOV A,R1
  RLC A
  MOV R1,A
  JNC DISP1
  JB 00H,EXIT
;----------------------------------
  SETB 00H
  CLR C
  MOV R1,#01H
  MOV R6,#29H
  MOV R7,#0FFH
    AJMP DISP1
EXIT:    MOV R6,#28H
  MOV R7,#0ffH
  CLR 00H
  POP 00H
  RET
;---------------------------------------------------------------
DEL1:    MOV R2,#05H
DELY:    PUSH 02H
DEL2:    PUSH 02H
DEL3:    PUSH 02H
DEL4:    DJNZ R2,DEL4
  CALL DISPW
  POP 02H
  DJNZ R2,DEL3
  POP 02H
  DJNZ R2,DEL2
  POP 02H
  DJNZ R2,DELY
  RET
;---------------------------------------------------------
OFFLED:   MOV DPTR,#XPA
  MOV A,#0FFH
  MOVX @DPTR,A
  MOV DPTR,#XPB      

五、代码详解

#include <reg51.h>
#include <absacc.h>
#include <intrins.h>

#define uchar unsigned char

#define com8255 XBYTE[0xff2b]//宏定义口地址
#define pa8255 XBYTE[0xff28]
#define pb8255 XBYTE[0xff29]
#define pc8255 XBYTE[0xff2a]

/*--  文字:  张  --*/
/*--  宋体12;  此字体下对应的点阵为：宽x高=16x16   --*/
/*--  0x01,0x00,0xF9,0x08,0x09,0x08,0x09,0x10,0x09,0x20,0x79,0x40,0x41,0x00,0x47,0xFE,
 0x41,0x40,0x79,0x20,0x09,0x20,0x09,0x10,0x09,0x08,0x09,0x44,0x51,0x82,0x21,0x00   --*/

/*--  文字:  三  --*/
/*--  宋体12;  此字体下对应的点阵为：宽x高=16x16   --*/
/*--  0x00,0x00,0x00,0x00,0x7F,0xFC,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x3F,0xF8,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xFF,0xFE,0x00,0x00,0x00,0x00   --*/

uchar code zhang[35] = {0x01,0x00,0xF9,0x08,0x09,0x08,0x09,0x10,0x09,0x20,0x79,0x40,0x41,0x00,0x47,0xFE, 0x41,0x40,0x79,0x20,0x09,0x20,0x09,0x10,0x09,0x08,0x09,0x44,0x51,0x82,0x21,0x00};
uchar code san[35] = {0x00,0x00,0x00,0x00,0x7F,0xFC,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x3F,0xF8,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xFF,0xFE,0x00,0x00,0x00,0x00};

void main(void)
{
  com8255 = 0x80; //控制口赋值

  while (1)
  {
    unsigned int i = 0, j = 0, k = 0, nn = 0;
    unsigned int x = 0, y = 0;

    unsigned int tag = 0;
    //张
    while (1)
    {
      for (i = 0; i < 32; i = i + 2)
      {
        x = 0, y = 0;
        j = 1 << (15 - i / 2);
        pc8255 = j >> 8;
        P1 = j - ((j >> 8) << 8);

        k = ((zhang[i]) << 8) + (zhang[i + 1]);
        for (nn = 0; nn < 8; nn++)
        {
          if (k >> nn & 1)
            x = (x << 1) + 1;
          else
            x = x << 1;
        }
        for (nn = 8; nn < 16; nn++)
        {
          if (k >> nn & 1)
            y = (y << 1) + 1;
          else
            y = y << 1;
        }

        pb8255 = ~x;
        pa8255 = ~y;
      }
      tag++;
      if (tag == 50)
        break;
    }
    tag = 0;

    //三
    while (1)
    {
      for (i = 0; i < 32; i = i + 2)
      {
        x = 0, y = 0;
        j = 1 << (15 - i / 2);
        pc8255 = j >> 8;
        P1 = j - ((j >> 8) << 8);

        k = ((san[i]) << 8) + (san[i + 1]);
        for (nn = 0; nn < 8; nn++)
        {
          if (k >> nn & 1)
            x = (x << 1) + 1;
          else
            x = x << 1;
        }
        for (nn = 8; nn < 16; nn++)
        {
          if (k >> nn & 1)
            y = (y << 1) + 1;
          else
            y = y << 1;
        }

        pb8255 = ~x;
        pa8255 = ~y;
      }
      tag++;
      if (tag == 50)
        break;
    }
    tag = 0;
  }
}