这题是斐波那契博弈(Fibonacci Nim)
详情戳这个链接:http://blog.csdn.net/dgq8211/article/details/7602807
代码如下
#include<iostream>
using namespace std;
int main()
{
int n, fun[45] = {0,2,3};
for(int i = 3; i <= 45; i++)
fun[i] = fun[i-1] + fun[i-2];
while(cin >> n && n)
{
int i;
for(i = 1; i <= 45; i++)
if(fun[i] == n) break;
if(i < 45) cout << "Second win" << endl;
else cout << "First win" << endl;
}
return 0;
}