描述下场景,比如一个人有多个qq号(假设一个人可以有重复的qq号)
数据库结构,有两张表:
people表
id name
1 jack
people_qq表
id people_id qq
1 1 123456
2 1 234567
3 1 456789
4 1 123456
实体类:
import java.io.Serializable;
import java.util.List;
public class People implements Serializable{
private static final long serialVersionUID = -5935066186174346694L;
private Long id;
private String name;
private List<String> qqs;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public List<String> getQqs() {
return qqs;
}
public void setQqs(List<String> qqs) {
this.qqs = qqs;
}
@Override
public String toString() {
return "People [id=" + id + ", name=" + name + ", qqs=" + qqs + "]";
}
}
mapper接口:
import com.hnpicheng.mybatisissue.domain.People;
public interface PeopleMapper {
People selectPeopleById( Long id);
}
测试代码:
import org.springframework.context.support.ClassPathXmlApplicationContext;
import com.hnpicheng.mybatisissue.domain.People;
import com.hnpicheng.mybatisissue.mapper.PeopleMapper;
public class App
{
public static void main( String[] args )
{
ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("spring-mybatis.xml");
PeopleMapper peopleMapper = context.getBean(PeopleMapper.class);
People p = peopleMapper.selectPeopleById(1L);
System.out.println(p);
}
}
PeopleMapper.xml
根据业务需要,如果不需要将重复数据查出来:
那么可以使用
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE mapper PUBLIC "-//mybatis.org//DTD Mapper 3.0//EN" "http://mybatis.org/dtd/mybatis-3-mapper.dtd">
<mapper namespace="com.hnpicheng.mybatisissue.mapper.PeopleMapper">
<resultMap id="peopleResultMap" type="People">
<id property="id" column="id" />
<result property="name" column="name" />
<collection property="qqs" ofType="string" javaType="list">
<result column="qq" />
</collection>
</resultMap>
<select id="selectPeopleById" resultMap="peopleResultMap">
select p.*,pq.qq from
people p left join people_qq pq on p.id = pq.people_id
where p.id = #{id}
</select>
</mapper>
测试结果,优点只要查一次,对于需要排重的查询业务,可以用这个方法:
DEBUG [main] - ==> Preparing: select p.*,pq.qq from people p left join people_qq pq on p.id = pq.people_id where p.id = ?
DEBUG [main] - ==> Parameters: 1(Long)
DEBUG [main] - <== Total: 4
People [id=1, name=jack, qqs=[123456, 234567, 456789]]
若果需要将重复数据查询出来,那么可以使用以下配置
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE mapper PUBLIC "-//mybatis.org//DTD Mapper 3.0//EN" "http://mybatis.org/dtd/mybatis-3-mapper.dtd">
<mapper namespace="com.hnpicheng.mybatisissue.mapper.PeopleMapper">
<resultMap id="peopleResultMap" type="People">
<id property="id" column="id" />
<result property="name" column="name" />
<collection property="qqs" column="id" select="selectQQByPeopleId"> 这里的column是指调用selectQQByPeopleId传递的参数
<result column="qq" />
</collection>
</resultMap>
<select id="selectPeopleById" resultMap="peopleResultMap">
select * from people where id = #{id}
</select>
<select id="selectQQByPeopleId" resultType="string">
select qq from people_qq where people_id = #{id}
</select>
</mapper>
测试结果:
DEBUG [main] - ==> Preparing: select * from people where id = ?
DEBUG [main] - ==> Parameters: 1(Long)
DEBUG [main] - <== Total: 1
DEBUG [main] - ==> Preparing: select qq from people_qq where people_id = ?
DEBUG [main] - ==> Parameters: 1(Long)
DEBUG [main] - <== Total: 4
People [id=1, name=jack, qqs=[123456, 234567, 456789, 123456]]