leetcode刷题十二

题目叙述

题目解答

class Solution:
    def backspaceCompare(self, s: str, t: str) -> bool:
        news = []
        newt = []
        for i in s:
            if i == "#":
                if len(news) > 0:
                    news.pop()
            else:
                news.append(i)
        for i in t:
            if i == "#":
                if len(newt) > 0:
                    newt.pop()
            else:
                newt.append(i)
        print(news)
        print(newt)
        return news ==