递归求阶乘n!:
public class Factorial {
public static void main(String[] args){
System.out.println(factorial(9));
}
//递归求阶乘n!
public static int factorial(int n){
if(n==1||n==0){
return 1;
}else{
return n*factorial(n-1);
}
}
递归求Fibonacci数列:1,1,2,3,5,8...第9个数的值。数列满足递推公式:
f(1)=1,f(2)=1 f(n)=f(n-1)+f(n-2)(n>2)
public class Fibonacci {
public static void main(String[] args) {
System.out.println(fibonacci(9));
System.out.println(noRecursionFibonacci(9));
//递归求fibonacci的值
public static int fibonacci(int n){
if(n==1||n==2){
return fibonacci(n-1)+fibonacci(n-2);
//非递归求fibonacci的值(迭代)
public static int noRecursionFibonacci(int n){
int f1 = 1;
int f2 = 1;
int f3 = 1;
for(int i=0;i<n-2;i++){
f3 = f2+f1;
f1=f2;
f2=f3;
return f3;
本文转自 yzzh9 51CTO博客,原文链接:http://blog.51cto.com/java999/168085,如需转载请自行联系原作者