The application of the equal sum line theorem in the college entrance examination is the key to solving such problems is actually to make parallel lines and convert them into distance ratios. If the vector iconOP = xOA + yOB, the AP is handed over to A
The application of the equal sum line theorem in the college entrance examination
The key to solving such problems is actually to make parallel lines, which translate into the ratio of distance. If the vector iconOP = xOA+ yOB, AP crosses AB at Q, then A, B, Q three points collinear, through P as AB parallel line cross OA, OB at A₁, B₁, set vector OP = μOQ, by the triangle similarity can get x + y = μ = O to A₁ B₁ distance / O to AB distance
The application of the equal sum line theorem in the college entrance examination is the key to solving such problems is actually to make parallel lines and convert them into distance ratios. If the vector iconOP = xOA + yOB, the AP is handed over to A
The application of the equal sum line theorem in the college entrance examination is the key to solving such problems is actually to make parallel lines and convert them into distance ratios. If the vector iconOP = xOA + yOB, the AP is handed over to A
The application of the equal sum line theorem in the college entrance examination is the key to solving such problems is actually to make parallel lines and convert them into distance ratios. If the vector iconOP = xOA + yOB, the AP is handed over to A
The application of the equal sum line theorem in the college entrance examination is the key to solving such problems is actually to make parallel lines and convert them into distance ratios. If the vector iconOP = xOA + yOB, the AP is handed over to A
