Problem Description
Given a positive integer N, you should output the most right digit of N^N.
Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single positive integer N(1<=N<=1,000,000,000).
Output
For each test case, you should output the rightmost digit of N^N.
Sample Input
2
3
4
Sample Output
7
6
Hint
In the first case, 3 * 3 * 3 = 27, so the rightmost digit is 7.
In the second case, 4 * 4 * 4 * 4 = 256, so the rightmost digit is 6.
#include<cstdio>
#include<queue>
#include<stack>
#include<cstring>
#include<vector>
#include<map>
#include<iostream>
#include<algorithm>
#include<functional>
using namespace std;
int main()
{
int n,T;
cin>>T;
while (T--)
{
cin>>n;
int i,j,k;
for (i=n,j=n%10,k=1;i;i>>=1)
{
if (i&1) k=k*j%10;
j=j*j%10;
}
cout<<k<<endl;
}
return 0;
}