11.查詢至少有一門課與學号為“01”的同學所學相同的同學的學号和姓名
select stu.sid
from
(
select other.s sid,other.c cid
from
(
select cid from sc where sid=01
) s01
join
(
select sid s,cid c from sc where sid!=01
) other
on other.c=s01.cid
) stu
group by stu.sid
having count(cid)>=1;
12.查詢和"01"号的同學學習的課程完全相同的其他同學的學号和姓名
select stu.sid,count(cid)
from
(
select other.s sid,other.c cid
from
(
select cid from sc where sid=1
) s01
left join
(
select sid s,cid c from sc where sid!=01
) other
on other.c=s01.cid
) stu
group by stu.sid
having count(cid)=3;
13.查詢兩門及其以上不及格課程的同學的學号,姓名及其平均成績
select sid,count(score) c,round(avg(score),1) from sc where score<60 group by sid having c>=2;
14.檢索"01"課程分數小于60,按分數降序排列的學生資訊
select sid,score s from sc where cid=01 and score<60 order by s desc;
15.按平均成績從高到低顯示所有學生的所有課程的成績以及平均成績
select nvl(c12.sid,c3.sid),c12.c1,c12.c2,nvl(c3.score,0),round((c12.c1+c12.c2+nvl(c3.score,0))/3,1) avg
from
(
select nvl(c1.sid,c2.sid) sid,nvl(c1.score,0) c1,nvl(c2.score,0) c2
from
(
select sid,score from sc where cid=1
) c1
full join
(
select sid,score from sc where cid=2
) c2
on c1.sid=c2.sid
) c12
full join
(
select sid,score from sc where cid=3
) c3
on c12.sid=c3.sid
order by avg desc;
16.查詢各科成績最高分、最低分和平均分:以如下形式顯示:課程ID,課程name,最高分,最低分,平均分,及格率,中等率,優良率,優秀率
select c.cid,course.cname,c.max,c.min,c.avg,c.ge60,c.ge60lt70,c.ge70lt80,c.ge80lt90,c.ge90
from course
join
(
select cid,max(score) max,min(score) min,round(avg(score),1) avg,
round(sum(case when score>=60 then 1 else 0 end)/count(cid),3) ge60,
round(sum(case when score>=60 and score<70 then 1 else 0 end)/count(cid),3) ge60lt70,
round(sum(case when score>=70 and score<80 then 1 else 0 end)/count(cid),3) ge70lt80,
round(sum(case when score>=80 and score<90 then 1 else 0 end)/count(cid),3) ge80lt90,
round(sum(case when score>=90 then 1 else 0 end)/count(cid),3) ge90
from sc group by cid
) c
on c.cid=course.cid;
17.查詢學生的總成績并進行排名
select sid,t.s,row_number()over(order by t.s desc)
from
(
select sid,sum(score) s from sc group by sid
) t;
18.查詢不同老師所教不同課程平均分從高到低顯示
select c.cid,course.tid,c.avg
from course
join
(
select cid,round(avg(score),1) avg from sc group by cid
) c
on course.cid=c.cid
order by c.avg desc;
19.查詢每門課程被選修的學生數
select cid,count(sid) from sc group by cid;
20.查詢出隻選修了一門課程的全部學生的學号和姓名
select sid,count(cid) from sc group by sid having count(cid)=1;