C# XML 的序列化和反序列化

1.xml 集合序列化和發序列化

1.1 對象結構

public class People
     {
       [XmlAttribute("NAME")]
       public string Name
       { set; get; }
       [XmlAttribute("AGE")]
       public int Age
       { set; get; }
     }
     [XmlRoot("Root")]
     public class Student : People
     {
       [XmlElement("CLASS")]
       public string Class
       { set; get; }
       [XmlElement("NUMBER")]
       public int Number
       { set; get; }
     }      

2.對象序列化為 xml 檔案

public void ToXML()
     {      List<Student> stuList = new List<Student>();
       stuList.Add(new Student() { Age = 10, Number = 1, Name = "Tom", Class = "Class One" });
       stuList.Add(new Student() { Age = 11, Number = 2, Name = "Jay", Class = "Class Two" });
       stuList.Add(new Student() { Age = 12, Number = 3, Name = "Pet", Class = "Class One" });
       stuList.Add(new Student() { Age = 13, Number = 4, Name = "May", Class = "Class Three" });
       stuList.Add(new Student() { Age = 14, Number = 5, Name = "Soy", Class = "Class Two" });
       XmlSerializer ser = new XmlSerializer(typeof(List<Student>));
       ser.Serialize(File.Create("C:\\x.xml"), stuList);    }      

3.序列化後 xml 内容

<?xml version="1.0"?>

<ArrayOfStudent xmlns:xsi="​​​http://www.w3.org/2001/XMLSchema-instance​​​" xmlns:xsd="​​http://www.w3.org/2001/XMLSchema​​​">

  <Student NAME="Tom" AGE="10">

    <CLASS>Class One</CLASS>

    <NUMBER>1</NUMBER>

  </Student>

  <Student NAME="Jay" AGE="11">

    <CLASS>Class Two</CLASS>

    <NUMBER>2</NUMBER>

  </Student>

  <Student NAME="Pet" AGE="12">

    <CLASS>Class One</CLASS>

    <NUMBER>3</NUMBER>

  </Student>

  <Student NAME="May" AGE="13">

    <CLASS>Class Three</CLASS>

    <NUMBER>4</NUMBER>

  </Student>

  <Student NAME="Soy" AGE="14">

    <CLASS>Class Two</CLASS>

    <NUMBER>5</NUMBER>

  </Student>

</ArrayOfStudent>

4.将 xml 反序列化為對象

public List<Student> ToStudent()
     {
       XmlSerializer ser = new XmlSerializer(typeof(List<Student>));
       List<Student> stuList = ser.Deserialize(File.OpenRead("C:\\x.xml")) as List<Student>;      return stuList;
     }      

5.測試腳本

5.1測試類

public class Test
   {
     public class People
     {
       [XmlAttribute("NAME")]
       public string Name
       { set; get; }
       [XmlAttribute("AGE")]
       public int Age
       { set; get; }
     }
     [XmlRoot("Root")]
     public class Student : People
     {
       [XmlElement("CLASS")]
       public string Class
       { set; get; }
       [XmlElement("NUMBER")]
       public int Number
       { set; get; }
     }      

public void ToXML()
     {      List<Student> stuList = new List<Student>();
       stuList.Add(new Student() { Age = 10, Number = 1, Name = "Tom", Class = "Class One" });
       stuList.Add(new Student() { Age = 11, Number = 2, Name = "Jay", Class = "Class Two" });
       stuList.Add(new Student() { Age = 12, Number = 3, Name = "Pet", Class = "Class One" });
       stuList.Add(new Student() { Age = 13, Number = 4, Name = "May", Class = "Class Three" });
       stuList.Add(new Student() { Age = 14, Number = 5, Name = "Soy", Class = "Class Two" });
       XmlSerializer ser = new XmlSerializer(typeof(List<Student>));
       ser.Serialize(File.Create("C:\\x.xml"), stuList);    }      

public List<Student> ToStudent()
     {
       XmlSerializer ser = new XmlSerializer(typeof(List<Student>));
       List<Student> stuList = ser.Deserialize(File.OpenRead("C:\\x.xml")) as List<Student>;      return stuList;
     }   }      

private void btnOk_Click(object sender, EventArgs e)
     {
       Test t = new Test();
       t.ToXML();
       t.ToStudent();
     }