select * from user where nick_name in
(select nick_name from user group by nick_name having count(nick_name)>1);
2、查出有重複記錄的各個記錄組中id最大的記錄
select * from user where id in (select max(id) from user group by nick_name having count(nick_name)>1);
3、查出多餘的記錄,不查出id最小的記錄
select * from user where nick_name in
(select nick_name from user group by nick_name having count(nick_name)>1)
and id not in
(select min(id) from user group by nick_name having count(nick_name)>1);
4、删除多餘的重複記錄,隻保留id最小的記錄
delete from user where nick_name in
(select nick_name from
(select nick_name from user group by nick_name having count(nick_name)>1) as tmp1)
and id not in
(select id from
(select min(id) from user group by nick_name having count(nick_name)>1) as tmp2);
二、多字段(nick_name,password)
1、查出所有有重複記錄的記錄
select * from user where (nick_name,password) in
(select nick_name,password from user group by nick_name,password where having count(nick_name)>1);
2、查出有重複記錄的各個記錄組中id最大的記錄
select * from user where id in
(select max(id) from user group by nick_name,password where having count(nick_name)>1);
3、查出各個重複記錄組中多餘的記錄資料,不查出id最小的一條
select * from user where (nick_name,password) in
(select nick_name,password from user group by nick_name,password having count(nick_name)>1)
and id not in
(select min(id) from user group by nick_name,password having count(nick_name)>1);
4、删除多餘的重複記錄,隻保留id最小的記錄
delete from user where (nick_name,password) in
(select nick_name,password from
(select nick_name,password from user group by nick_name,password having count(nick_name)>1) as tmp1)
and id not in
(select id from
(select min(id) id from user group by nick_name,password having count(nick_name)>1) as tmp2);