部落客福利:100G+電子設計學習資源包!
http://mp.weixin.qq.com/mp/homepage?__biz=MzU3OTczMzk5Mg==&hid=7&sn=ad5d5d0f15df84f4a92ebf72f88d4ee8&scene=18#wechat_redirect --------------------------------------------------------------------------------------------------------------------------
步進電機控制應用執行個體
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設計要求:
- 采用定時中斷方式控制步進機的轉速,定時機關時長為10ms。
- 速度設定在1/2/3/4四個檔位,1檔最快,依次遞減,能夠控制步進電機的停、轉和方向,同時顯示步進機的目前檔位。
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設計思路:
- 通過P1控制步進電機的轉動,P1.0->a,P1.1->b,P1.2->c,P1.3->d,ULN2003A作為步進電機驅動
- P2.0-P2.3對應數位管顯示(使用7447晶片對應将BCD碼轉換成7端LED數位管),通過7447簡單驅動數位管(P2隻需要發送1/2/3/4即可)
- 通過定時器計數,到達設定值時步進電機轉動1/4圈,計數清零
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元件清單:
- AT89C51
- BUTTON
- MOTOR-STEPPER
- RESPACK-8
- 7SEG-COM-ANODE
- ULN2003A
- 7447
#include <reg52.h>
typedef unsigned char uchar;
uchar direction = 0; //0為正轉,1為反轉
uchar onoff = 0; //關為0,開為1
uchar n = 0; //每次定時器中斷觸發時n++,當n==max時電機轉動1/4
uchar max = 10;
uchar index = 0; //通過index訓示電機轉動,AB,BC,CD,DA
sbit LED = P3 ^ 7; //當n==max時LED閃爍提示
int main()
{
/* LED */
P2 = 0xff;
/* 初始化中斷 */
EA = 1;
EX0 = 1; //要用到的中斷是兩個外部中斷和定時器中斷0
IT0 = 1;
EX1 = 1;
IT1 = 1;
ET0 = 1;
/* 定時器0 */
TMOD = 0x01; //使用定時器0,方式1
TH0 = (65536 - 10000) / 256; //12MHz晶振下,定時器為10ms觸發中斷,更友善觀察轉動情況
TL0 = (65536 - 10000) % 256;
TR0 = 1;
while(1)
{
switch(P0)
{
case 0xfe: //11111110
max = 1;
P2 = 1;
break;
case 0xfd: //11111101
max = 10;
P2 = 2;
break;
case 0xfb: //11111011
max = 50;
P2 = 3;
break;
case 0xf7: //11110111
max = 100;
P2 = 4;
break;
}
}
}
void Stop()interrupt 0
{
onoff++;
if (onoff > 1)
onoff = 0;
}
void int1()interrupt 2
{
direction++;
if (direction > 1)
direction = 0;
}
void delay50ms(void)
{
unsigned char a, b;
for(b = 173; b > 0; b--)
for(a = 143; a > 0; a--);
}
void time()interrupt 1
{
TH0 = (65536 - 10000) / 256;
TL0 = (65536 - 10000) % 256;
if (onoff == 1) //在開狀态下
{
if (n == max) //設定檔位速度,經過了max次中斷後,步進電機轉1/4圈
{
LED = 0; //每次n==max時LED閃爍
delay50ms();
LED = 1;
if (direction == 0)
{
switch(index) //正轉時以AB,BC,CD,DA順序
{
case 0:P1 = 0x03;break; //00000011 AB高電平
case 1:P1 = 0x06;break; //00000110 BC高電平
case 2:P1 = 0x0c;break; //00001100 CD高電平
case 3:P1 = 0x09;break; //00001001 DA高電平
}
index ++;
if (index == 4) //步進電機轉完一圈時index清零
index = 0;
n = 0; //到達max,n重置為0
}
if (direction == 1)
{
switch(index) //反轉時以DA,CD,BC,AB順序
{
case 0:P1 = 0x09;break;
case 1:P1 = 0x0c;break;
case 2:P1 = 0x06;break;
case 3:P1 = 0x03;break;
}
index ++;
if (index == 4)
index = 0;
n = 0;
}
else n = 0;
}
n++; //n!=max時,n++
}
else n = 0; //在關狀态下,n始終為0,無法觸發電機轉動
}