題目描述:
翻轉一棵二叉樹。
示例:
輸入:
4
/ \
2 7
/ \ / \
1 3 6 9
輸出:
4
/ \
7 2
/ \ / \
9 6 3 1
算法思想:将二叉樹的右子樹換成左子樹,左子樹換成右子樹
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* invertTree(TreeNode* root) {
if(root==NULL)
return NULL;
TreeNode* left=invertTree(root->right);
TreeNode* right=invertTree(root->left);
root->left=left;
root->right=right;
return root;
}
};
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* invertTree(TreeNode* root) {
if(root){
swap(root->left,root->right);//對于兩個指針的指向(位址)進行交換
invertTree(root->left);
invertTree(root->right);
}
return root;
}
};