🔥group by應用場景🔥
我們已經掌握使用select語句結合where查詢條件擷取需要的資料,但在實際的應用中,還會遇到下面這類需求,又該如何解決?
1、公司想知道每個部門有多少員工
2、班主任想統計各科成績的第一名
3、某門店想掌握男、女性會員的人數和平均年齡
🔥group by的使用🔥
從字面上了解,group by表示根據某種規則對資料進行分組,它必須配合聚合函數進行使用,對資料進行分組後可以進行count、sum、avg、max和min等運算。
group by文法
SELECT column_name,aggregate_function(column_name) FROM table_name GROUP BY column_name
說明:
1、aggregate_function 表示聚合函數
mysql> alter table employee add column dept varchar(20) comment '部門名稱';
Query OK, 0 rows affected (0.06 sec)
Records: 0 Duplicates: 0 Warnings: 0
mysql> desc employee;
+--------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------+-------------+------+-----+---------+----------------+
| id | int | NO | PRI | NULL | auto_increment |
| name | varchar(30) | YES | | NULL | |
| sex | varchar(1) | YES | | NULL | |
| salary | int | YES | | NULL | |
| dept | varchar(20) | YES | | NULL | |
+--------+-------------+------+-----+---------+----------------+
5 rows in set (0.00 sec)
mysql> update employee set dept='部門A' where id='1';
Query OK, 1 row affected (0.01 sec)
Rows matched: 1 Changed: 1 Warnings: 0
mysql> update employee set dept='部門B' where id='2';
Query OK, 1 row affected (0.01 sec)
Rows matched: 1 Changed: 1 Warnings: 0
mysql> update employee set dept='部門B' where id='3';
Query OK, 1 row affected (0.01 sec)
Rows matched: 1 Changed: 1 Warnings: 0
mysql> select * from employee;
+----+--------+------+--------+-------+
| id | name | sex | salary | dept |
+----+--------+------+--------+-------+
| 1 | 張三 | 男 | 5500 | 部門A |
| 2 | 李四 | 男 | 4500 | 部門B |
| 3 | 張小妹 | 女 | 4500 | 部門B |
+----+--------+------+--------+-------+
3 rows in set (0.00 sec)select sex,count(*) from employee group by sex;
+------+----------+
| sex | count(*) |
+------+----------+
| 男 | 2 |
| 女 | 1 |
+------+----------+
2 rows in set (0.00 sec)select dept,count(*) from employee group by dept;
+-------+----------+
| dept | count(*) |
+-------+----------+
| 部門A | 1 |
| 部門B | 2 |
+-------+----------+
2 rows in set (0.00 sec)select dept,sum(salary) from employee group by dept;
+-------+-------------+
| dept | sum(salary) |
+-------+-------------+
| 部門A | 5500 |
| 部門B | 9000 |
+-------+-------------+
2 rows in set (0.00 sec)select dept,sum(salary) from employee group by dept;
+-------+-------------+
| dept | sum(salary) |
+-------+-------------+
| 部門A | 5500 |
| 部門B | 9000 |
+-------+-------------+
2 rows in set (0.00 sec)select dept,min(salary) from employee group by dept;
+-------+-------------+
| dept | min(salary) |
+-------+-------------+
| 部門A | 5500 |
| 部門B | 4500 |
+-------+-------------+
2 rows in set (0.00 sec)
🔥 having的使用 🔥
SELECT column_name,aggregate_function(column_name)
FROM table_name WHERE column_name operator value
GROUP BY column_name HAVING aggregate_function(column_name) operator valuemysql> select dept, count(*) from employee group by dept;
+-------+----------+
| dept | count(*) |
+-------+----------+
| 部門A | 1 |
| 部門B | 2 |
+-------+----------+
2 rows in set (0.00 sec)
mysql> select dept, count(*) from employee group by dept having count(*)<2;
+-------+----------+
| dept | count(*) |
+-------+----------+
| 部門A | 1 |
+-------+----------+
1 row in set (0.00 sec)
mysql> select dept, count(*) from employee group by dept having count(*)<3;
+-------+----------+
| dept | count(*) |
+-------+----------+
| 部門A | 1 |
| 部門B | 2 |
+-------+----------+
2 rows in set (0.00 sec)mysql> select dept, max(salary) from employee group by dept;
+-------+-------------+
| dept | max(salary) |
+-------+-------------+
| 部門A | 5500 |
| 部門B | 4500 |
+-------+-------------+
2 rows in set (0.00 sec)
mysql> select dept,max(salary) from employee group by dept having max(salary)>=5000;
+-------+-------------+
| dept | max(salary) |
+-------+-------------+
| 部門A | 5500 |
+-------+-------------+
1 row in set (0.00 sec)