@https://pintia.cn/problem-sets/15/problems/730
6-7 在一個數組中實作兩個堆棧 (20 point(s))
本題要求在一個數組中實作兩個堆棧。
函數接口定義:
Stack CreateStack( int MaxSize );
bool Push( Stack S, ElementType X, int Tag );
ElementType Pop( Stack S, int Tag );
其中
Tag
是堆棧編号,取
1
或
2
;
MaxSize
堆棧數組的規模;
Stack
結構定義如下:
typedef int Position;
struct SNode {
ElementType *Data;
Position Top1, Top2;
int MaxSize;
};
typedef struct SNode *Stack;
注意:如果堆棧已滿,
Push
函數必須輸出“
Stack Full
”并且傳回
false
;如果某堆棧是空的,則
Pop
函數必須輸出“
Stack Tag Empty
”(其中
Tag
是該堆棧的編号),并且傳回
ERROR
。
裁判測試程式樣例:
#include <stdio.h>
#include <stdlib.h>
#define ERROR 1e8
typedef int ElementType;
typedef enum { push, pop, end } Operation;
typedef enum { false, true } bool;
typedef int Position;
struct SNode {
ElementType *Data;
Position Top1, Top2;
int MaxSize;
};
typedef struct SNode *Stack;
Stack CreateStack( int MaxSize );
bool Push( Stack S, ElementType X, int Tag );
ElementType Pop( Stack S, int Tag );
Operation GetOp(); /* details omitted */
void PrintStack( Stack S, int Tag ); /* details omitted */
int main()
{
int N, Tag, X;
Stack S;
int done = 0;
scanf("%d", &N);
S = CreateStack(N);
while ( !done ) {
switch( GetOp() ) {
case push:
scanf("%d %d", &Tag, &X);
if (!Push(S, X, Tag)) printf("Stack %d is Full!\n", Tag);
break;
case pop:
scanf("%d", &Tag);
X = Pop(S, Tag);
if ( X==ERROR ) printf("Stack %d is Empty!\n", Tag);
break;
case end:
PrintStack(S, 1);
PrintStack(S, 2);
done = 1;
break;
}
}
return 0;
}
/* 你的代碼将被嵌在這裡 */
輸入樣例:
5
Push 1 1
Pop 2
Push 2 11
Push 1 2
Push 2 12
Pop 1
Push 2 13
Push 2 14
Push 1 3
Pop 2
End
輸出樣例:
Stack 2 Empty
Stack 2 is Empty!
Stack Full
Stack 1 is Full!
Pop from Stack 1: 1
Pop from Stack 2: 13 12 11
代碼實作©
Stack CreateStack(int MaxSize)
{
Stack p = (Stack)malloc(sizeof(struct SNode));
p->Data = (int*)malloc(MaxSize * sizeof(int));
p->Top1 =- 1;
p->Top2 = MaxSize;
p->MaxSize = MaxSize;
return p;
}
bool Push(Stack S, ElementType X, int Tag)
{
if (S->Top2 - S->Top1 == 1)
{
puts("Stack Full");
return 0;
}
if (Tag == 1)
S->Data[++(S->Top1)] = X;
else S->Data[--(S->Top2)] = X;
return 1;
}
ElementType Pop(Stack S, int Tag)
{
if (Tag == 1)
{
if (S->Top1 == -1)
{
printf("Stack %d Empty\n", Tag);
return ERROR;
}
return S->Data[(S->Top1)--];
}
else
{
if (S->Top2 == S->MaxSize)
{
printf("Stack %d Empty\n", Tag);
return ERROR;
}
return S->Data[(S->Top2)++];
}
}