問題 A: Least Common Multiple
時間限制: 1 Sec 記憶體限制: 32 MB
送出: 442 解決: 208
[送出][狀态][讨論版][命題人:外部導入]
題目描述
The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.
輸入
Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.
輸出
樣例輸入
2
2 3 5
3 4 6 12
樣例輸出
15
12
#include<iostream>
#include<algorithm>
using namespace std;
const int N=1e6;
int a[N];
int T,n;
bool isAllDiv(int x){
for(int i=0;i<n;i++){
if(x%a[i]!=0) return false;
}
return true;
}
int main(){
cin>>T;
while(T--){
cin>>n;
for(int i=0;i<n;i++){
cin>>a[i];
}
int max=*max_element(a,a+n);
for(int i=1;;i++){
if(isAllDiv(max*i)){
cout<<max*i<<endl;
break;
}
}
}
return 0;
}