本題要求在一個數組中實作兩個堆棧。
函數接口定義:
Stack CreateStack( int MaxSize );
bool Push( Stack S, ElementType X, int Tag );
ElementType Pop( Stack S, int Tag );
其中
Tag
是堆棧編号,取1或2;
MaxSize
堆棧數組的規模;
Stack
結構定義如下:
typedef int Position;
struct SNode {
ElementType *Data;
Position Top1, Top2;
int MaxSize;
};
typedef struct SNode *Stack;
注意:如果堆棧已滿,
Push
函數必須輸出“Stack Full”并且傳回false;如果某堆棧是空的,則
Pop
函數必須輸出“Stack Tag Empty”(其中Tag是該堆棧的編号),并且傳回ERROR。
裁判測試程式樣例:
#include <stdio.h>
#include <stdlib.h>
#define ERROR 1e8
typedef int ElementType;
typedef enum { push, pop, end } Operation;
typedef enum { false, true } bool;
typedef int Position;
struct SNode {
ElementType *Data;
Position Top1, Top2;
int MaxSize;
};
typedef struct SNode *Stack;
Stack CreateStack( int MaxSize );
bool Push( Stack S, ElementType X, int Tag );
ElementType Pop( Stack S, int Tag );
Operation GetOp(); /* details omitted */
void PrintStack( Stack S, int Tag ); /* details omitted */
int main()
{
int N, Tag, X;
Stack S;
int done = 0;
scanf("%d", &N);
S = CreateStack(N);
while ( !done ) {
switch( GetOp() ) {
case push:
scanf("%d %d", &Tag, &X);
if (!Push(S, X, Tag)) printf("Stack %d is Full!\n", Tag);
break;
case pop:
scanf("%d", &Tag);
X = Pop(S, Tag);
if ( X==ERROR ) printf("Stack %d is Empty!\n", Tag);
break;
case end:
PrintStack(S, 1);
PrintStack(S, 2);
done = 1;
break;
}
}
return 0;
}
/* 你的代碼将被嵌在這裡 */
輸入樣例:
5
Push 1 1
Pop 2
Push 2 11
Push 1 2
Push 2 12
Pop 1
Push 2 13
Push 2 14
Push 1 3
Pop 2
End
輸出樣例:
Stack 2 Empty
Stack 2 is Empty!
Stack Full
Stack 1 is Full!
Pop from Stack 1: 1
Pop from Stack 2: 13 12 11
題解:
用一個棧實作兩個棧的資料的存放,我的思路是用tag=1時棧頂指針指向-1,入棧後top++;tag=2時棧頂就存放在棧的最大容量開始,每次入棧,top--;
當然棧内元素下标Tag=1時是從Top1==0開始,Tag =2時是從Top2==MaxSize-1開始。
當傳入的Tag=1時就調用Top1棧頂,如果傳入的Tag=2時就調用Top2棧頂,實作共享棧。
點選了解共享棧是什麼
以下是代碼:
Stack CreateStack( int MaxSize )
{
Stack k;
k = (Stack)malloc(sizeof(struct SNode));
k->Data= (int *)malloc(MaxSize*sizeof(int));
k->Top1=-1;
k->MaxSize=MaxSize;
k->Top2=MaxSize;
return k;
}
bool Push( Stack S, ElementType X, int Tag )
{
if(S->Top1 == S->Top2-1)
{
printf("Stack Full\n");
return false;
}
if(Tag==1){
S->Top1++;
S->Data[S->Top1]=X;
}else if(Tag==2){
S->Top2--;
S->Data[S->Top2]=X;
}
return true;
}
ElementType Pop( Stack S, int Tag )
{
int num;
if(Tag==1){
if(S->Top1==-1){
printf("Stack %d Empty\n",Tag);
return ERROR;
}else{
return S->Data[S->Top1--];
}
}else if(Tag==2){
if(S->Top2==S->MaxSize){
printf("Stack %d Empty\n",Tag);
return ERROR;
}else{
return S->Data[S->Top2++];
}
}
}