hdu-6308（輸出格式，時間轉換）

Time Zone

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 2849    Accepted Submission(s): 902

Problem Description

Chiaki often participates in international competitive programming contests. The time zone becomes a big problem.

Given a time in Beijing time (UTC +8), Chiaki would like to know the time in another time zone s.

Input

There are multiple test cases. The first line of input contains an integer T (1≤T≤106), indicating the number of test cases. For each test case:

The first line contains two integers a, b (0≤a≤23,0≤b≤59) and a string s in the format of "UTC+X'', "UTC-X'', "UTC+X.Y'', or "UTC-X.Y'' (0≤X,X.Y≤14,0≤Y≤9).

Output

For each test, output the time in the format of hh:mm (24-hour clock).

Sample Input

3 11 11 UTC+8 11 12 UTC+9 11 23 UTC+0

Sample Output

11:11 12:12 03:23

Source

2018 Multi-University Training Contest 1

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心得：輸入的格式要注意，按照題目中的來。

将第8時區時間化為分鐘，求要到達的時區和第8時區之間的內插補點，再加上原來第八時區的時間

注意，‘+’還是‘-’，‘-’的話要最後變為正數。

#include<bits/stdc++.h>
using namespace std;
int main(void)
{
	int h,m,t;
	double d;
	char ch;
	int t1,t2,tp;
	while(~scanf("%d",&t))
	{
		while(t--)
		{
			scanf("%d %d UTC%c%lf",&h,&m,&ch,&d);
			t1=h*60+m;
			tp=(int)(d*10);
			if(ch=='+')
			{
				t2=t1+tp*6-8*60;
			}
			else if(ch=='-')
			{
				t2=t1-tp*6-8*60;
			}
			t2=t2%(24*60);
			if(t2<0) t2+=24*60;
			h=t2/60;
			m=t2%60;
			printf("%02d:%02d\n",h,m);
		}
	}
	return 0;
}