//#pragma comment(linker, "/STACK:1024000000,1024000000")
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<algorithm>
#include<iostream>
#include<sstream>
#include<cmath>
#include<climits>
#include<string>
#include<map>
#include<queue>
#include<vector>
#include<stack>
#include<set>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int> pii;
#define pb(a) push(a)
#define INF 0x1f1f1f1f
#define lson idx<<1,l,mid
#define rson idx<<1|1,mid+1,r
#define PI 3.1415926535898
template<class T> T min(const T& a,const T& b,const T& c) {
return min(min(a,b),min(a,c));
}
template<class T> T max(const T& a,const T& b,const T& c) {
return max(max(a,b),max(a,c));
}
void debug() {
#ifdef ONLINE_JUDGE
#else
freopen("d:\\in1.txt","r",stdin);
freopen("d:\\out1.txt","w",stdout);
#endif
}
int getch() {
int ch;
while((ch=getchar())!=EOF) {
if(ch!=' '&&ch!='\n')return ch;
}
return EOF;
}
struct Edge
{
int u,v;
};
const double eps=10e-6;
const int maxn=100005;
double x;
int age[maxn];
struct TwoSat
{
int n;
int mark[maxn*2];
vector<int> g[maxn*2];
int s[maxn],c;
void init(int n)
{
this->n=n;
for(int i=0;i<n*2;i++)
g[i].clear();
memset(mark,0,sizeof(mark));
}
void add_clause(int u,int v)
{
g[u].push_back(v);
}
bool dfs(int u)
{
if(mark[u^1])return false;
if(mark[u])return true;
mark[u]=1;
s[c++]=u;
for(int i=0;i<g[u].size();i++)
{
if(!dfs(g[u][i]))return false;
}
return true;
}
bool solve()
{
for(int i=0;i<n*2;i+=2)
{
if(!mark[i]&&!mark[i+1])
{
c=0;
if(!dfs(i))
{
while(c)mark[s[--c]]=0;
if(!dfs(i+1))return false;
}
}
}
return true;
}
};
int n,m;
TwoSat solver;
bool same(int a,int b)
{
if(age[a]>=x&&age[b]>=x)return true;
if(age[a]<x&&age[b]<x)return true;
return false;
}
int main()
{
while(scanf("%d%d",&n,&m)!=EOF&&(n||m))
{
x=0;
solver.init(n);
for(int i=0;i<n;i++)
{
scanf("%d",&age[i]);
x+=age[i];
}
x/=n;
for(int i=0;i<m;i++)
{
int u,v;
scanf("%d%d",&u,&v);
u--;v--;
if(same(u,v))
{
solver.add_clause(u*2,v*2+1);
solver.add_clause(u*2+1,v*2);
solver.add_clause(v*2,u*2+1);
solver.add_clause(v*2+1,u*2);
}else
{
solver.add_clause(u*2,v*2+1);
solver.add_clause(v*2,u*2+1);
}
}
bool res=solver.solve();
if(!res)
printf("No solution.\n");
else
{
for(int i=0;i<n;i++)
{
if(solver.mark[i*2])
{
printf("C\n");
}else
{
printf("%c\n",age[i]>=x?'A':'B');
}
}
}
}
return 0;
}
View Code
轉載于:https://www.cnblogs.com/BMan/p/3612612.html