用java玩acm

第一次用java寫acm程式

HDU1000

http://acm.hdu.edu.cn/showproblem.php?pid=1000

A + B Problem

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 154095    Accepted Submission(s): 48841

Problem Description Calculate A + B.

  Input Each line will contain two integers A and B. Process to end of file.

  Output For each case, output A + B in one line.

  Sample Input

1 1
        

  Sample Output

2
        

Author HDOJ

代碼如下：

import java.util.Scanner;

public class Main
{
	public static void main(String args[])
	{
		int a,b;
		Scanner keyIn = new Scanner(System.in);
		while(keyIn.hasNext())
		{
		a = keyIn.nextInt();
		b = keyIn.nextInt();
		System.out.println(a+b);
	  }
	}
}
           

這裡第一次用java玩acm的注意：

1，主類所在類的類名一定是Main，即是main方法所在類

2，循環輸入的問題，在C++我們可以用while(scanf("%d",&a)!=EOF),但是在java中我們用的是 掃描類的hasNext（）函數來判斷是否結束輸入，另外注意導入Scanner類