Numbers can be regarded as product of its factors. For example,
8 = 2 x 2 x 2;
= 2 x 4.
Write a function that takes an integer n and return all possible combinations of its factors.
Note:
- You may assume that n is always positive.
- Factors should be greater than 1 and less than n.
Examples:
input:
1
output:
[]
input:
37
output:
[]
input:
12
output:
[
[2, 6],
[2, 2, 3],
[3, 4]
]
input:
32
output:
[
[2, 16],
[2, 2, 8],
[2, 2, 2, 4],
[2, 2, 2, 2, 2],
[2, 4, 4],
[4, 8]
]
public class Solution {
public List<List<Integer>> getFactors(int n) {
List<List<Integer>> res = new ArrayList<List<Integer>>();
if (n <= 1) {
return res;
}
List<Integer> list = new ArrayList<Integer>();
factors(n, list, res, 2);
return res;
}
public void factors(int n, List<Integer> list, List<List<Integer>> res, int start) {
if (n == 1) {
if (list.size() > 1) {
res.add(new ArrayList<Integer>(list));
}
return;
}
for (int i = start; i <= n; i++) {
if (n % i == 0) {
list.add(i);
factors(n / i, list, res, i);
list.remove(list.size() - 1);
}
}
}
}
i從start開始,而不是每次都從2開始。