原文: WPF 獲得DataGridRow和 DataGridCell的方法 原文位址
簡介
在WPF中,DataGrid控件并沒有提供通路其DataGridRow或者DataGridCell的方法。
是以我們需要自己來編寫擷取的方法,這其中主要用到了ItemsControl類的一個執行個體方法:ItemContainerGenerator。
實作代碼
using System.Windows.Controls;
using System.Windows.Controls.Primitives;
using System.Windows.Media;
namespace Splash.WPF
{
public static class DataGridPlus
{
/// <summary>
/// 擷取DataGrid控件單元格
/// </summary>
/// <param name="dataGrid">DataGrid控件</param>
/// <param name="rowIndex">單元格所在的行号</param>
/// <param name="columnIndex">單元格所在的列号</param>
/// <returns>指定的單元格</returns>
public static DataGridCell GetCell(this DataGrid dataGrid, int rowIndex, int columnIndex)
{
DataGridRow rowContainer = dataGrid.GetRow(rowIndex);
if (rowContainer != null)
{
DataGridCellsPresenter presenter = GetVisualChild<DataGridCellsPresenter>(rowContainer);
DataGridCell cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(columnIndex);
if (cell == null)
{
dataGrid.ScrollIntoView(rowContainer, dataGrid.Columns[columnIndex]);
cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(columnIndex);
}
return cell;
}
return null;
}
/// <summary>
/// 擷取DataGrid的行
/// </summary>
/// <param name="dataGrid">DataGrid控件</param>
/// <param name="rowIndex">DataGrid行号</param>
/// <returns>指定的行号</returns>
public static DataGridRow GetRow(this DataGrid dataGrid, int rowIndex)
{
DataGridRow rowContainer = (DataGridRow)dataGrid.ItemContainerGenerator.ContainerFromIndex(rowIndex);
if (rowContainer == null)
{
dataGrid.UpdateLayout();
dataGrid.ScrollIntoView(dataGrid.Items[rowIndex]);
rowContainer = (DataGridRow)dataGrid.ItemContainerGenerator.ContainerFromIndex(rowIndex);
}
return rowContainer;
}
/// <summary>
/// 擷取父可視對象中第一個指定類型的子可視對象
/// </summary>
/// <typeparam name="T">可視對象類型</typeparam>
/// <param name="parent">父可視對象</param>
/// <returns>第一個指定類型的子可視對象</returns>
public static T GetVisualChild<T>(Visual parent) where T : Visual
{
T child = default(T);
int numVisuals = VisualTreeHelper.GetChildrenCount(parent);
for (int i = 0; i < numVisuals; i++)
{
Visual v = (Visual)VisualTreeHelper.GetChild(parent, i);
child = v as T;
if (child == null)
{
child = GetVisualChild<T>(v);
}
if (child != null)
{
break;
}
}
return child;
}
}
}