vim /data/mysqlback.sh
#! /bin/bash
BAKPATH=/data/mysql-back
MYUSER=root
MYPASS="123456"
SOCKET=/var/lib/mysql/mysql.sock
MYCMD="mysql -u$MYUSER -p$MYPASS -S $SOCKET"
MYDUMP="mysqldump -u$MYUSER -p$MYPASS -S $SOCKET -x -F -R"
DBLIST=`$MYCMD -e "show databases;" |sed "1d" |egrep -v "_schema|test"`
[ ! -d $BAKPATH ] && mkdir -p $BAKPATH
for dbname in $DBLIST
do
TLIST=`$MYCMD -e "show tables from $dbname;" |sed "1d"`
for tname in $TLIST
do
mkdir -p $BAKPATH/$dbname
$MYDUMP $dbname $tname |gzip > $BAKPATH/$dbname/${tname}_$(date +%F).sql.gz
done
done
執行腳本後可以看到對資料庫進行了分庫分表的操作
<a href="https://s3.51cto.com/wyfs02/M01/8C/BC/wKiom1h14IGDU4JwAAD65ty_Z2I386.png" target="_blank"></a>
執行腳本提示警告:
-- Warning: Skipping the data of table mysql.event. Specify the --events option explicitly.
原因:mysqldump預設是不備份事件表
解決方法1:
在mysqldump指令後面添加--events參數
MYDUMP="mysqldump -u$MYUSER -p$MYPASS -S $SOCKET -x -F -R --events"
解決方法2:
在mysqldump指令後面添加--events --ignore-table=mysql.events 參數
MYDUMP="mysqldump -u$MYUSER -p$MYPASS -S $SOCKET -x -F -R --events --ignore-table=mysql.events"
報錯參考解決方案:
<a href="http://www.linuxbrigade.com/warning-skipping-data-table-mysql-event/" target="_blank">http://www.linuxbrigade.com/warning-skipping-data-table-mysql-event/</a>
<a href="http://bugs.mysql.com/bug.php?id=68376" target="_blank">http://bugs.mysql.com/bug.php?id=68376</a>
本文轉自M四月天 51CTO部落格,原文連結:http://blog.51cto.com/msiyuetian/1891098,如需轉載請自行聯系原作者