準備(兩張表t1,t2):
表t1:
mysql> select * from t1;
+-------+---------+
| t1_id | t1_name |
| 1 | t1_1 |
| 2 | t1_2 |
2 rows in set (0.02 sec)
表t2:
mysql> select * from t2;
| t2_id | t2_name |
| 2 | t2_2 |
| 3 | t2_3 |
2 rows in set (0.03 sec)
并集執行個體:
mysql> select t1.t1_id,t2.t2_id,t1.t1_name from t1 left join t2 on t1.t1_id=t2.t2_id;
+-------+-------+---------+
| t1_id | t2_id | t1_name |
| 1 | NULL | t1_1 |
| 2 | 2 | t1_2 |
交集執行個體:
mysql> select t1.t1_id,t2.t2_id,t1.t1_name from t1,t2 where t1.t1_id=t2.t2_id;
1 row in set (0.01 sec)
本文轉自 Lee_吉 部落格,原文連結: http://blog.51cto.com/12173069/1968871 如需轉載請自行聯系原作者