在某些情況下熟悉SQL Server 通配符的使用可以幫助我們簡單的解決很多問題。
--使用_運算符查找Person表中以an結尾的三字母名字
USEAdventureWorks2012;
GO
SELECT FirstName, LastName
FROM Person.Person
WHERE FirstName LIKE'_an'
ORDER BY FirstName;
---使用[^]運算符在Contact表中查找所有名字以Al開頭且第三個字母不是字母a的人
WHERE FirstName LIKE'Al[^a]%'
---使用[]運算符查找其位址中有四位郵政編碼的所有Adventure Works雇員的ID和姓名
SELECT e.BusinessEntityID, p.FirstName, p.LastName, a.PostalCode
FROMHumanResources.EmployeeAS e
INNER JOIN Person.PersonAS pON e.BusinessEntityID= p.BusinessEntityID
INNER JOIN Person.BusinessEntityAddressAS eaON e.BusinessEntityID=ea.BusinessEntityID
INNER JOIN Person.AddressAS aON a.AddressID= ea.AddressID
WHERE a.PostalCodeLIKE'[0-9][0-9][0-9][0-9]';
結果集:
EmployeeID FirstName LastName PostalCode
---------- --------- --------- ----------
290 Lynn Tsoflias 3000
--将一張表中名字為中英文的區分出來
create table tb(namenvarchar(20))
insert into tbvalues('kevin')
insert into tbvalues('kevin劉')
insert into tbvalues('劉')
select *,'Eng'from tbwherepatindex('%[a-z]%',name)>0and(patindex('%[吖-坐]%',name)=0)
union all
select *,'CN'from tbwherepatindex('%[吖-坐]%',name)>0andpatindex('%[a-z]%',name)=0
union all
select *,'Eng&CN'from tbwhere(patindex('%[吖-坐]%',name)>0)andpatindex('%[a-z]%',name)>0
name
-------------------- ------
kevin Eng
劉 CN
kevin劉 Eng&CN
(3 row(s) affected)
本文轉自 lzf328 51CTO部落格,原文連結:
http://blog.51cto.com/lzf328/1032126