這個也是Tom大神寫的工具。
https://asktom.oracle.com/pls/asktom/f?p=100:11:::::P11_QUESTION_ID:1163635055580
下面模拟沒有綁定變量的環境,然後使用該工具檢視
建立實驗帳号
conn / as sysdba
create user edmond identified by edmond;
grant connect,resource,dba to edmond;
create table t(x int);
insert into t select rownum from dual connect by level<=10000;
create or replace procedure p1
as
l_cnt number;
begin
for i in 1 .. 10000
loop
execute immediate 'select count(*) from t where x=' || i into l_cnt;
end loop;
end;
/
在一個終端執行p1過程,開啟另一個終端執行如下腳本:
create table t1 as select sql_text from v$sqlarea;
alter table t1 add sql_text_wo_constants varchar2(1000);
create or replace function
remove_constants( p_query in varchar2 ) return varchar2
l_query long;
l_char varchar2(1);
l_in_quotes boolean default FALSE;
for i in 1 .. length( p_query )
l_char := substr(p_query,i,1);
if ( l_char = '''' and l_in_quotes )
then
l_in_quotes := FALSE;
elsif ( l_char = '''' and NOT l_in_quotes )
l_in_quotes := TRUE;
l_query := l_query || '''#';
end if;
if ( NOT l_in_quotes ) then
l_query := l_query || l_char;
l_query := translate( l_query, '0123456789', '@@@@@@@@@@' );
for i in 0 .. 8 loop
l_query := replace( l_query, lpad('@',10-i,'@'), '@' );
l_query := replace( l_query, lpad(' ',10-i,' '), ' ' );
return upper(l_query);
update t1 set sql_text_wo_constants = remove_constants(sql_text);
set linesize 200;
col sql_text_wo_constants format a100;
select sql_text_wo_constants, count(*)
from t1
group by sql_text_wo_constants
having count(*) > 100
order by 2
可以看到結果如下,已經找到了沒有綁定變量的語句。
![](https://img.laitimes.com/img/_0nNw4CM6IyYiwiM6ICdiwiInBnauMWO1ATNkljMjZjZyUDNwUmZkljZwMDZ4EzY2QTM0cTYfdWbp9CXt92Yu4GZjlGbh5SZslmZxl3Lc9CX6MHc0RHaiojIsJye.jpg)