传送门
题意:
思路:
#include<bits/stdc++.h>
using namespace std;
#define ll long long
ll a[100];
int main()
{
int t;
cin>>t;
for(int i = 1; i <= 60; i++)
{
a[i] = pow(2,i-1);
}
while(t--)
{
ll n;
cin>>n;
int cnt = 0;
ll now = 1;
for(int i = 1; i <= 64; i++)
{
now *= 2;
if(now >= n)
{
cnt = i-1;
break;
}
}
ll ans = 0;
for(int i = 1; i <= cnt; i++)
{
ans += a[i];
}
cout<<ans<<endl;
}
}