问题描述
试题编号: 201903-1
试题名称: 小中大
时间限制: 1.0s
内存限制: 512.0MB
![](https://img.laitimes.com/img/__Qf2AjLwojIjJCLyojI0JCLiAzNfRHLGZkRGZkRfJ3bs92YsYTMfVmepNHL5lkeNFTU65UMRpHW4Z0MMBjVtJWd0ckW65UbM5WOHJWa5kHT20ESjBjUIF2X0hXZ0xCMx81dvRWYoNHLrdEZwZ1Rh5WNXp1bwNjW1ZUba9VZwlHdssmch1mclRXY39CXldWYtlWPzNXZj9mcw1ycz9WL49zZuBnLyQTMyIDN1IjMxEjMxAjMwIzLc52YucWbp5GZzNmLn9Gbi1yZtl2Lc9CX6MHc0RHaiojIsJye.png)
AC
#include<bits/stdc++.h>
using namespace std;
int main() {
int n;
cin>>n;
int a[n];
for(int i=0; i<n; i++) {
cin>>a[i];
}
int min,max;
if(a[0]<a[n-1]) {
min=a[0];
max=a[n-1];
} else {
min=a[n-1];
max=a[0];
}
cout<<max<<" ";
if(n%2==0) {
int x=a[n/2]+a[n/2-1];
if(x%2==0)
cout<<x/2<<" ";
else {
double mid=x;
printf("%.1f ",mid/2);
}
} else {
cout<<a[n/2]<<" ";
}
cout<<min;
return 0;
}