程序需求:能被4整除但不能被100整除,或者年被400整除的年份是闰年。编程写一个完整的程序,求出2012年~2099年中的所有闰年年份,把它们存放在数组Lyear中并输出到屏幕上。
编程思路:汇编中ESI用来做年份计数器,ECX用来做闰年个数计数器,用DIV指令来求余数。
开发环境
Win10 + VS2017
C语言代码实现如下:
#include <stdio.h>
int main()
{
printf("Leap year is follow:\n");
for (int i = 2012; i < 2100; i++)
{
if ((i % 4 == 0 && i % 100 != 0) || (i % 400 == 0))
printf("%d\t",i);
}
return 0;
}
汇编语言代码实现如下:
INCLUDELIB kernel32.lib
INCLUDELIB ucrt.lib
INCLUDELIB legacy_stdio_definitions.lib
.386
.model flat,stdcall
ExitProcess PROTO,
dwExitCode:DWORD
printf PROTO C : dword,:vararg
scanf PROTO C : dword,:vararg
.data
Lyear dword 25 dup(0)
msg byte 'Leap year is follow:',10,0
format byte '%d',9,0
.code
main Proc
xor ecx,ecx
mov esi,2012
jmp testing
body:
mov eax,esi
mov ebx,4
cdq
div ebx
cmp edx,0
jne next
mov eax,esi
mov ebx,100
cdq
div ebx
cmp edx,0
je next
mov dword ptr Lyear[ecx*4],esi
inc ecx
jmp over
next:
mov eax,esi
mov ebx,400
cdq
div ebx
cmp edx,0
jne over
mov dword ptr Lyear[ecx*4],esi
inc ecx
over:
inc esi
testing:
cmp esi,2100
jl body
pushad
invoke printf,offset msg
popad
xor esi,esi
again:
pushad
invoke printf,offset format,dword ptr Lyear[esi*4]
popad
inc esi
loop again
push 0h
call ExitProcess
main endp
end main
编译运行后结果如下:
![](https://img.laitimes.com/img/9ZDMuAjOiMmIsIjOiQnIsICM38FdsYkRGZkRG9lcvx2bjxiNx8VZ6l2cs0TP3NmeS5mWwx2MMBjVtJWd0ckW65UbM5WOHJWa5kHT20ESjBjUIF2X0hXZ0xCMx81dvRWYoNHLrdEZwZ1Rh5WNXp1bwNjW1ZUba9VZwlHdssmch1mclRXY39CXldWYtlWPzNXZj9mcw1ycz9WL49zZuBnL0YjNzUjN1MTM0EDNwkTMwIzLc52YucWbp5GZzNmLn9Gbi1yZtl2Lc9CX6MHc0RHaiojIsJye.png)