HDU-2586 How far away ?
题目
分析
#include <bits/stdc++.h>
#define INF 0x3f3f3f3f
#define d(x) cout << (x) << endl
#define lson l, m, rt<<1
#define rson m+1, r, rt<<1|1
#pragma GCC diagnostic error "-std=c++11"
using namespace std;
typedef long long ll;
const int mod = 1e9 + 7;
const int N = 4e4 + 10;
const int M = 2e2 + 10;
int t, n, m;
int cnt, num;
struct edge{
int next, to, w;
} e[N];
int head[N];
struct node{
int next, to;
int index; //查询序号
} ask[N];
int h[N];
int fa[N]; //并查集
int rt[N]; //求根节点
int vis[N]; //标记数组
int dis[N]; //节点到根节点权值
int ans[N]; //最后答案
void add(int x, int y, int w)
{
e[cnt].to = y;
e[cnt].w = w;
e[cnt].next = head[x];
head[x] = cnt++;
}
void addask(int u, int v, int index)
{
ask[num].to = v;
ask[num].next = h[u];
ask[num].index = index;
h[u] = num++;
ask[num].to = u;
ask[num].next = h[v];
ask[num].index = index;
h[v] = num++;
}
void init()
{
cnt = num = 0;
memset(head, -1, sizeof(head));
memset(h, -1, sizeof(h));
memset(vis, 0, sizeof(vis));
memset(rt, 0, sizeof(rt));
memset(dis, 0, sizeof(dis));
for (int i = 1; i <= n; i++){
fa[i] = i;
}
}
int find(int x)
{
return fa[x] = fa[x] == x ? x : find(fa[x]);
}
int tarjian(int rt)
{
for (int i = head[rt]; i != -1; i = e[i].next){
int x = e[i].to;
dis[x] = dis[rt] + e[i].w;
tarjian(x);
fa[x] = rt;
}
vis[rt] = 1;
for (int i = h[rt]; i != -1; i = ask[i].next){
int x = ask[i].to;
if(vis[x]){
ans[ask[i].index] = dis[rt] + dis[x] - 2 * dis[find(x)];
}
}
}
void solve()
{
int x, y, w, r;
scanf("%d%d", &n, &m);
init();
for (int i = 1; i < n; i++){
scanf("%d%d%d", &x, &y, &w);
add(x, y, w);
rt[y]++;
}
for(int i = 1; i <= n; i++){
if(!rt[i]){
r = i; break;
}
}
for (int i = 1; i <= m; i++){
scanf("%d%d", &x, &y);
addask(x, y, i);
}
tarjian(r);
for(int i = 1; i <= m; i++){
printf("%d\n", ans[i]);
}
}
int main()
{
scanf("%d", &t);
while(t--){
solve();
}
return 0;
}