串口通信检验和

校验和:

发送方的检验和位 byte为

_sum = 2^n - (sum(data) & 2 ^n-1)

接收方检测：

((sum(data) + _sum) & (2^n-1))

如果为0则检验正确

byte[] buf = new byte[12];
            buf[0] = 0XEB;
            buf[1] = 0x91;
            buf[2] = 0x00;
            buf[3] = 0x01;
            buf[4] = 0x10;


            buf[5] = 0x00;
            buf[6] = 0x00;
            buf[7] = 0x00;
            buf[8] = 0x00;
            buf[9] = 0x00;
            buf[10] = 0x00;

            buf[11] = 0x00;

            // _sum = 2 ^ n - (sum(data) & (2 ^ n - 1))

            byte sum = 0x00;
            for (int i = 0; i <= 10; i++)
            {
                sum += buf[i];
            }

            buf[11] = (byte)(0x100 - (sum & 0xFF));


            byte receive = (byte)((sum + buf[11]) & (0xff));