【学习笔记】【JAVA】处理跳转链接，获取重定向地址

【参考资料】：Java 获取网络302重定向URL的方法

【代码展示】

/**
	 * 处理跳转链接，获取重定向地址
	 * 
	 * @param url
	 *            源地址
	 * @return 目标网页的绝对地址
	 */
	public static String getAbsUrl(String url) {
		CloseableHttpClient httpclient = HttpClients.createDefault();
		HttpClientContext context = HttpClientContext.create();
		HttpGet httpget = new HttpGet(url);
		CloseableHttpResponse response = null;
		String absUrl = null;
		try {
			response = httpclient.execute(httpget, context);
			HttpHost target = context.getTargetHost();
			List<URI> redirectLocations = context.getRedirectLocations();
			// System.out.println("httpget.getURI()：" + httpget.getURI());
			URI location = URIUtils.resolve(httpget.getURI(), target, redirectLocations);
			// System.out.println("Final HTTP location: " +
			// location.toASCIIString());
			absUrl = location.toASCIIString();
		} catch (IOException e) {
			e.printStackTrace();
		} catch (Exception e) {
			e.printStackTrace();
		} finally {
			try {
				httpclient.close();
				response.close();
			} catch (IOException e) {
				e.printStackTrace();
			}
		}
		return absUrl;
	}