思路:
字典储存对应括号
遍历字符串:
左括号入栈
右括号分三种情况:
1.若此时栈为空,直接返回False
2.若此时右括号和栈顶左括号不匹配,直接返回False
3.若此时右括号和栈顶左括号匹配,栈顶左括号出栈
遍历结束后
若栈为空栈,说明所有括号都匹配完成,返回True
否则,返回False
class Solution:
def isValid(self, s: str) -> bool:
dic = {'(':')','[':']','{':'}'}
stack = []
for i in s:
if i in dic:
stack.append(i)
else:
if len(stack) == 0:
return False
elif i == dic[stack.pop()]:
pass
else:
return False
return len(stack) == 0
