获取url上参数

export const getUrlQuery = (name, url) => {

if (!url) {

url = window.location.href;

}

name = name.replace(/[[]]/g, '\KaTeX parse error: Expected 'EOF', got '&' at position 1: &̲'); const reg…{name}(=([^&#]*)|&|#|$)`),

results = regex.exec(url);

if (!results) return null;

if (!results[2]) return ‘’;

return decodeURIComponent(results[2].replace(/+/g, ’ '));

};